Here is my code to run the server:
class MyRequestHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
#....
PORT = 8089
httpd = SocketServer.TCPServer(("", PORT), MyRequestHandler)
httpd.allow_reuse_address = True
print "Serving forever at port", PORT
try:
httpd.serve_forever()
except:
print "Closing the server."
httpd.server_close()
raise
Yet this is what happens:
^CClosing the server.
Traceback (most recent call last):
File "server.py", line 118, in <module>
self.send_error(400, "Unimplemented GET command: %s" % (self.path,))
File "/home/claudiu/local/lib/python2.6/SocketServer.py", line 224, in serve_forever
r, w, e = select.select([self], [], [], poll_interval)
KeyboardInterrupt
(.virtualenv)claudiu@xxx:~/xxx$ python server.py
Traceback (most recent call last):
File "server.py", line 122, in <module>
httpd = SocketServer.TCPServer(("", PORT), MyRequestHandler)
File "/home/claudiu/local/lib/python2.6/SocketServer.py", line 402, in __init__
self.server_bind()
File "/home/claudiu/local/lib/python2.6/SocketServer.py", line 413, in server_bind
self.socket.bind(self.server_address)
File "<string>", line 1, in bind
socket.error: [Errno 98] Address already in use
Why? I close the server and set allow_reuse_address
to True... Using python 2.6.8.
expcept OSError: port+=1 ...
but python does not catch the port error (ON python 3.7 it gives OSError Exception rather than socket.error exception) – Spitfire