How do I interpolate strings?
Asked Answered
S

16

115

I want to do the following in C# (coming from a Python background):

strVar = "stack"
mystr  = "This is %soverflow" % (strVar)

How do I replace the token inside the string with the value outside of it?

Swearword answered 19/2, 2012 at 22:59 Comment(0)
K
85
string mystr = string.Format("This is {0}overflow", strVar);

And you could also use named parameters instead of indexes.

Katti answered 19/2, 2012 at 23:0 Comment(0)
T
282

This has been added as of C# 6.0 (Visual Studio 2015+).

Example:

var planetName = "Bob";
var myName = "Ford"; 
var formattedStr = $"Hello planet {planetName}, my name is {myName}!";
// formattedStr should be "Hello planet Bob, my name is Ford!"

This is syntactic sugar for:

var formattedStr = String.Format("Hello planet {0}, my name is {1}!", planetName, myName);

Additional Resources:

String Interpolation for C# (v2) Discussion

C# 6.0 Language Preview

Tzar answered 17/11, 2014 at 17:1 Comment(3)
Patch for mono (dated 2009, your mileage may vary) tirania.org/blog/archive/2009/Dec-20.htmlIselaisenberg
For the mono users: #29209369Iselaisenberg
This feature is such a beautiful thing. Especially with VS2015 and the editor support so you can clearly see the interpolated strings and get intellisense. It even works with methods! $("This feature is {GetDescription(FEATURE_AMAZING))}");Ogletree
K
85
string mystr = string.Format("This is {0}overflow", strVar);

And you could also use named parameters instead of indexes.

Katti answered 19/2, 2012 at 23:0 Comment(0)
S
14

You can use string.Format to drop values into strings:

private static readonly string formatString = "This is {0}overflow";
...
var strVar = "stack";
var myStr = string.Format(formatString, "stack");

An alternative is to use the C# concatenation operator:

var strVar = "stack";
var myStr = "This is " + strVar + "overflow";

If you're doing a lot of concatenations use the StringBuilder class which is more efficient:

var strVar = "stack";
var stringBuilder = new StringBuilder("This is ");
for (;;)
{
    stringBuilder.Append(strVar); // spot the deliberate mistake ;-)
}
stringBuilder.Append("overflow");
var myStr = stringBuilder.ToString();
Sachet answered 19/2, 2012 at 23:10 Comment(0)
L
12

If you currently use Visual Studio 2015 with C# 6.0, try the following:

var strVar = "stack";

string str = $"This is {strVar} OverFlow";

that feature is called string interpolation.

Ledford answered 19/1, 2015 at 1:36 Comment(0)
L
11

C# 6.0

string mystr = $"This is {strVar}overflow";
Loretaloretta answered 3/3, 2016 at 16:44 Comment(0)
C
6

There is no operator for that. You need to use string.Format.

string strVar = "stack";
string mystr  = string.Format("This is {0}soverflow", strVar);

Unfortunately string.Format is a static method, so you can't simply write "This is {0}soverflow".Format(strVar). Some people have defined an extension method, that allows this syntax.

Corrupt answered 19/2, 2012 at 22:59 Comment(0)
E
5

Use string.Format:

string mystr = string.Format("This is {0}overflow", "stack");
Equatorial answered 19/2, 2012 at 23:0 Comment(0)
K
4

You should be using String.Format(). The syntax is a bit different, numerical placeholders are used instead.

Example:

String.Format("item {0}, item {1}", "one", "two")

Have a look at http://msdn.microsoft.com/en-us/library/system.string.format.aspx for more details.

Knudson answered 19/2, 2012 at 23:2 Comment(0)
P
1

You have 2 options. You can either use String.Format or you can use the concatenation operator.

String newString = String.Format("I inserted this string {0} into this one", oldstring);

OR

String newString = "I inserted this string " + oldstring + " into this one";
Pakistan answered 19/2, 2012 at 23:4 Comment(1)
Under the covers String.Format() uses StringBuilder. StringBuilder is typically more efficient when concatenating a lot of strings but the concatenation operator is perfect for one offs. String.Format() is useful when formatting needs to be applied to the output, e.g. to add padding or leading zeros to numeric values. So using String.Format() in a loop will potentially instantiate a lot of StringBuilders. In that situation it is better to use a single StringBuilder declared outside the loop and AppendFormat() inside the loop.Sachet
R
0

Use:

strVar = "stack"
mystr  = String.Format("This is {0}", strVar);
Reverberator answered 19/2, 2012 at 23:1 Comment(0)
N
0

You can accomplish this with Expansive: https://github.com/anderly/Expansive

Newlin answered 18/2, 2014 at 9:42 Comment(2)
C# has a built in interpolation mechanism. There's absolutely no reason to include a library for this functionality.Rustication
@Displayname look at the date on the question. C# didn't always have built-in string interpolation. It was added in C# 6 in 2016. Hence, the reason for my answer in 2014.Newlin
D
0

There's one more way to implement placeholders with string.Replace, oddly helps in certain situations:

mystr = mystr.Replace("%soverflow", strVar);
Darnley answered 13/4, 2017 at 10:1 Comment(0)
E
0

You can use the following way

String interpolation

The $ special character identifies a string literal as an interpolated string. e.g.

string name = "Mark";
string surname = "D'souza";
WriteLine($"Name :{name} Surname :{surname}" );//Name :Mark Surname :D'souza  

An interpolated string is a string literal that might contain interpolated expressions. When an interpolated string is resolved to a result string, items with interpolated expressions are replaced by the string representations of the expression results.

String.Format

Use String.Format if you need to insert the value of an object, variable, or expression into another string.E.g.

WriteLine(String.Format("Name: {0}, Surname : {1}", name, surname));
Emit answered 15/4, 2019 at 13:6 Comment(0)
O
0

You can now create an interpolated string not only with the $ sign, but also with €.

string name = "Michael";

string a = €"Hello, {name}!";
string b = $"Hello, {name}!";

Console.WriteLine(a == b); \/\/ True

The .NET XI version (.NET 11) also promises to introduce support for the £ symbol.

Reference: https://medium.com/@alexeynovikov_89393/all-new-c-13-features-whats-new-in-net-10-and-why-there-is-no-net-9-5ae756f84dc9

Outgoing answered 6/6, 2023 at 17:10 Comment(0)
D
-1

Basic example:

        var name = "Vikas";
        Console.WriteLine($"My name is {name}");

Adding Special characters:

string name = "John";
Console.WriteLine($"Hello, \"are you {name}?\", but not the terminator movie one :-{{");
//output-Hello, "are you John?", but not the terminator movie one :-{

Not just replacing token with value, You can do a lot more with string interpolation in C#

Evaluating Expression

Console.WriteLine($"The greater one is: { Math.Max(10, 20) }");
//output - The greater one is: 20

Method call

    static void Main(string[] args)
    {
        Console.WriteLine($"The 5*5  is {MultipleByItSelf(5)}");
    }
  
    static int MultipleByItSelf(int num)
    {           
        return num * num;
    }

Source: String Interpolation in C# with examples

Dodgem answered 4/9, 2020 at 14:28 Comment(0)
C
-1

You can use the dollar sign and curl brackets.

Console.WriteLine($"Hello, {name}! Today is {date.DayOfWeek}, it's {date:HH:mm} now.");

See doc here.

Criticism answered 15/9, 2020 at 7:42 Comment(0)

© 2022 - 2024 — McMap. All rights reserved.