I want to do the following in C# (coming from a Python background):
strVar = "stack"
mystr = "This is %soverflow" % (strVar)
How do I replace the token inside the string with the value outside of it?
I want to do the following in C# (coming from a Python background):
strVar = "stack"
mystr = "This is %soverflow" % (strVar)
How do I replace the token inside the string with the value outside of it?
string mystr = string.Format("This is {0}overflow", strVar);
And you could also use named parameters instead of indexes.
This has been added as of C# 6.0 (Visual Studio 2015+).
Example:
var planetName = "Bob";
var myName = "Ford";
var formattedStr = $"Hello planet {planetName}, my name is {myName}!";
// formattedStr should be "Hello planet Bob, my name is Ford!"
This is syntactic sugar for:
var formattedStr = String.Format("Hello planet {0}, my name is {1}!", planetName, myName);
Additional Resources:
$("This feature is {GetDescription(FEATURE_AMAZING))}");
–
Ogletree string mystr = string.Format("This is {0}overflow", strVar);
And you could also use named parameters instead of indexes.
You can use string.Format
to drop values into strings:
private static readonly string formatString = "This is {0}overflow";
...
var strVar = "stack";
var myStr = string.Format(formatString, "stack");
An alternative is to use the C# concatenation operator:
var strVar = "stack";
var myStr = "This is " + strVar + "overflow";
If you're doing a lot of concatenations use the StringBuilder
class which is more efficient:
var strVar = "stack";
var stringBuilder = new StringBuilder("This is ");
for (;;)
{
stringBuilder.Append(strVar); // spot the deliberate mistake ;-)
}
stringBuilder.Append("overflow");
var myStr = stringBuilder.ToString();
If you currently use Visual Studio 2015 with C# 6.0, try the following:
var strVar = "stack";
string str = $"This is {strVar} OverFlow";
that feature is called string interpolation.
C# 6.0
string mystr = $"This is {strVar}overflow";
There is no operator for that. You need to use string.Format
.
string strVar = "stack";
string mystr = string.Format("This is {0}soverflow", strVar);
Unfortunately string.Format
is a static method, so you can't simply write "This is {0}soverflow".Format(strVar)
. Some people have defined an extension method, that allows this syntax.
Use string.Format
:
string mystr = string.Format("This is {0}overflow", "stack");
You should be using String.Format()
. The syntax is a bit different, numerical placeholders are used instead.
Example:
String.Format("item {0}, item {1}", "one", "two")
Have a look at http://msdn.microsoft.com/en-us/library/system.string.format.aspx for more details.
You have 2 options. You can either use String.Format or you can use the concatenation operator.
String newString = String.Format("I inserted this string {0} into this one", oldstring);
OR
String newString = "I inserted this string " + oldstring + " into this one";
String.Format()
uses StringBuilder. StringBuilder is typically more efficient when concatenating a lot of strings but the concatenation operator is perfect for one offs. String.Format()
is useful when formatting needs to be applied to the output, e.g. to add padding or leading zeros to numeric values. So using String.Format()
in a loop will potentially instantiate a lot of StringBuilders. In that situation it is better to use a single StringBuilder declared outside the loop and AppendFormat()
inside the loop. –
Sachet Use:
strVar = "stack"
mystr = String.Format("This is {0}", strVar);
You can accomplish this with Expansive: https://github.com/anderly/Expansive
There's one more way to implement placeholders with string.Replace, oddly helps in certain situations:
mystr = mystr.Replace("%soverflow", strVar);
You can use the following way
String interpolation
The $ special character identifies a string literal as an interpolated string. e.g.
string name = "Mark";
string surname = "D'souza";
WriteLine($"Name :{name} Surname :{surname}" );//Name :Mark Surname :D'souza
An interpolated string is a string literal that might contain interpolated expressions. When an interpolated string is resolved to a result string, items with interpolated expressions are replaced by the string representations of the expression results.
String.Format
Use String.Format if you need to insert the value of an object, variable, or expression into another string.E.g.
WriteLine(String.Format("Name: {0}, Surname : {1}", name, surname));
You can now create an interpolated string not only with the $ sign, but also with €.
string name = "Michael";
string a = €"Hello, {name}!";
string b = $"Hello, {name}!";
Console.WriteLine(a == b); \/\/ True
The .NET XI version (.NET 11) also promises to introduce support for the £ symbol.
Basic example:
var name = "Vikas";
Console.WriteLine($"My name is {name}");
Adding Special characters:
string name = "John";
Console.WriteLine($"Hello, \"are you {name}?\", but not the terminator movie one :-{{");
//output-Hello, "are you John?", but not the terminator movie one :-{
Not just replacing token with value, You can do a lot more with string interpolation in C#
Evaluating Expression
Console.WriteLine($"The greater one is: { Math.Max(10, 20) }");
//output - The greater one is: 20
Method call
static void Main(string[] args)
{
Console.WriteLine($"The 5*5 is {MultipleByItSelf(5)}");
}
static int MultipleByItSelf(int num)
{
return num * num;
}
You can use the dollar sign and curl brackets.
Console.WriteLine($"Hello, {name}! Today is {date.DayOfWeek}, it's {date:HH:mm} now.");
See doc here.
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