When a C++ program is compiled. It needs to have references to the C++
library functions and code (say for example the code for the library).
Assume we have a hypothetical shared library called libdyno.so. You'll eventually be able to peek inside it using using objdump or nm.
objdump --syms libdyno.so
You can do this today on your system with any shared library. objdump on a MAC is called gobjdump and comes with brew in the binutils package. Try this on a mac...
gobjdump --syms /usr/lib/libz.dylib
You can now see that the symbols are contained in the shared object. When you link with the shared object you typically use something like
g++ -Wall -g -pedantic -ldyno DynoLib_main.cpp -o dyno_main
Note the -ldyno in that command. This is telling the compiler (really the linker ld) to look for a shared object file called libdyno.so wherever it normally looks for them. Once it finds that object it can then find the symbols it needs. There's no circular dependency because you the developer asked for the dynamic library to be loaded by specifying the -l flag.
How and when would you use a dynamic library? How do you make one? As in what
is the specific compiling command that is used to produce such a file from a
standard .cpp file
Create a file called DynoLib.cpp
#include "DynoLib.h"
DynamicLib::DynamicLib() {}
int DynamicLib::square(int a) {
return a * a;
}
Create a file called DynoLib.h
#ifndef DYNOLIB_H
#define DYNOLIB_H
class DynamicLib {
public:
DynamicLib();
int square(int a);
};
#endif
Compile them to be a shared library as follows. This is linux specific...
g++ -Wall -g -pedantic -shared -std=c++11 DynoLib.cpp -o libdyno.so
You can now inspect this object using the command I gave earlier ie
objdump --syms libdyno.so
Now create a file called DynoLib_main.cpp that will be linked with libdyno.so and use the function we just defined in it.
#include "DynoLib.h"
#include <iostream>
using namespace std;
int main(void) {
DynamicLib *lib = new DynamicLib();
std::cout << "Square " << lib->square(1729) << std::endl;
return 1;
}
Compile it as follows
g++ -Wall -g -pedantic -L. -ldyno DynoLib_main.cpp -o dyno_main
./dyno_main
Square 2989441
You can also have a look at the main binary using nm. In the following I'm seeing if there is anything with the string square in it ie is the symbol I need from libdyno.so in any way referenced in my binary.
nm dyno_runner |grep square
U _ZN10DynamicLib6squareEi
The answer is yes. The uppercase U means undefined but this is the symbol name for our square method in the DynamicLib Class that we created earlier. The odd looking name is due to name mangling which is it's own topic.
How do I know which ones to link to statically as I would with a regular
.o file and which ones are supposed to be dynamically linked with?
You don't need to know. You specify what you want to link with and let the compiler (and linker etc) do the work. Note the -l flag names the library and the -L tells it where to look. There's a decent write up on how the compiler finds thing here
gcc Linkage option -L: Alternative ways how to specify the path to the dynamic library
Or have a look at man ld.
What are the -L and -l flags for? What does it mean to specify
for example a -lusb flag on the command line?
See the above link. This is from man ld..
-L searchdir
Add path searchdir to the list of paths that ld will search for
archive libraries and ld control scripts. You may use this option any
number of times. The directories are searched in the order in which
they are specified on the command line. Directories specified on the
command line are searched before the default directories. All -L
options apply to all -l options, regardless of the order in which the
options appear. -L options do not affect how ld searches for a linker
script unless -T option is specified.`
If you managed to get here it pays dividends to learn about the linker ie ld. It plays an important job and is the source of a ton of confusion because most people start out dealing with a compiler and think that compiler == linker and this is not true.
