virtual-functions Questions
3
Solved
I have a confusion about the inheriting the virtual property of a method.
Let's suppose we have 4 classes: class A, class B, class C and class D.
The classes are inherited by this way: A -> B -> C...
Sanity asked 24/7, 2013 at 18:57
1
Solved
As I understand it, to pass/return polymorphic objects you need to use a pointer or reference type to prevent slicing problems. However, to return objects from functions you cannot create on stack ...
Wharton asked 7/7, 2013 at 14:42
2
To eliminate unused (ordinary) function I can use:
-ffunction-sections, -fdata-section and --gc-sections.
and it works.
I know that using polymorphism, function are 'late-binding' so I suppose the...
Papillote asked 2/7, 2013 at 19:6
2
Solved
What I want to do is for Execute() to run and completes it calls the Base::Done() then calls the Derived::Done(). I'm doing this because Base class Execute will do something and when its done call ...
Guimar asked 26/6, 2013 at 15:18
2
Solved
In this code:
class Base {
public:
virtual void method() = 0;
};
class Derived1 : public Base{
public:
virtual void method() override { }
};
class Derived2 : public Base{
public:
void method(...
Tranquillize asked 26/6, 2013 at 10:2
3
Solved
I was going through this:- https://isocpp.org/wiki/faq/multiple-inheritance#mi-delegate-to-sister
Can Someone give me an explaination of how does this happens and why does this happens?
Perorate asked 24/6, 2013 at 16:25
3
Solved
In Stack Overflow post Checking the object type in C++11, I have the comment:
In C++11 you'll actually want to do virtual ~A() = default; Otherwise, you'll lose the implict move constructors.
...
Nadiya asked 20/6, 2013 at 19:0
4
Solved
As all the virtual function in C++ is stored in V-table. Overiding takes place in the case of virtual function.
I want to ask there is any way by which we can call the Virtual function direct...
Touchmenot asked 14/6, 2013 at 10:29
4
Solved
I don't have a precise description of the problem so I'm just asking if this is possible (and if it is, some other information would be great).
A programmer told me you can avoid runtime overhead ...
Gabi asked 7/6, 2013 at 16:5
1
Solved
So basically I want to understand what are the general steps C# compiler takes to determine whether the method that is being called is nonvirtual instance method or virtual method.
Confusion comes...
Compensable asked 31/5, 2013 at 20:57
3
Solved
I'm reading Effective C++, and there is the "Item 9: Never call virtual functions during construction or destruction". And I'm wondering if my code is fine even if it breaks this rule:
using...
Wineglass asked 23/5, 2013 at 16:43
5
Solved
Is it essential to have a definition for a virtual function?
Consider this sample program below:
#include <iostream>
using namespace std;
class base
{
public:
void virtual virtualfunc()...
Insecurity asked 27/12, 2011 at 7:25
3
Solved
The following C++ code i think is correct, but produce some warnings when compiled with "-Woverloaded-virtual", is the warning bogus or there is a real problem with this code?
If that is a bogus w...
Frisky asked 3/4, 2012 at 14:32
2
Supressing C++ vtable generation can be done in MSVC using the __declspec(novtable) attribute. However, it seems that there is no equivalent attribute for the GNU C++ compiler. The fact is that lea...
Colloidal asked 3/12, 2011 at 22:17
3
The runtime type of all the calling instances is D hence, all the invocations of F() should be the F() method declared in D.
using System;
class A
{
public virtual void F() { Console.WriteLine("A...
Mestee asked 8/4, 2013 at 6:15
2
The error below is confusing me. Here is a short piece of a much more complicated code. It appears strange to me, that only the existence of both a templated constructor and a virtual method cause ...
Lupulin asked 4/4, 2013 at 0:12
2
Solved
I'm aware that a params modifier (which turns in one parameter of array type into a so-called "parameter array") is specifically not a part of the method signature. Now consider this example:
clas...
Cliff asked 2/4, 2013 at 21:15
4
Solved
I have this chunk of code:
#include <stdio.h>
class CoolClass {
public:
virtual void set(int x){x_ = x;};
virtual int get(){return x_;};
private:
int x_;
};
class PlainOldClass {
...
Spotter asked 1/4, 2013 at 11:12
2
Solved
Hopefully this isn't too specialized of a question for StackOverflow: if it is and could be migrated elsewhere let me know...
Many moons ago, I wrote a undergraduate thesis proposing various devir...
Countable asked 1/3, 2013 at 0:38
2
Solved
I have a pure abstract base and two derived classes:
struct B { virtual void foo() = 0; };
struct D1 : B { void foo() override { cout << "D1::foo()" << endl; } };
struct D2 : B { void ...
Daren asked 17/2, 2013 at 15:48
4
Solved
When i invoke a virtual function from a base constructor, the compiler does not give any error. But when i invoke a pure-virtual function from the base class constructor, it gives compilation error...
Abdel asked 27/12, 2011 at 7:59
2
Solved
Possible Duplicate:
Calling virtual functions inside constructors
main.cpp
#include <iostream>
class BaseClass {
public:
BaseClass() {
init();
}
virtual ~BaseClass() {...
Guenna asked 31/1, 2013 at 13:32
6
Solved
As I understand temporaries, the following code should work, but it doesn't.
struct base
{
virtual~base() {}
virtual void virt()const=0;
};
struct derived:public base
{
virtual void virt()const...
Herbage asked 23/1, 2013 at 22:50
1
Solved
I am trying to use std::bind() to create a function that will call the base class version of a virtual function rather than calling the derived class's version.
struct Base
{
virtual void foo() {...
Kolk asked 18/1, 2013 at 21:40
4
Solved
Possible Duplicate:
Can a member function template be virtual?
In a base class, the function my_func is defined as virtual. However, in the derived class I would like to have my_func ...
Diley asked 11/12, 2012 at 10:37
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