sprig-template-functions Questions

3

Solved

I am writing a Helm 3 library chart and would like to create a YAML with default values. However, when trying to set a default value for a nested key that does not exist, Helm fails with the follow...
Bodyguard asked 11/4, 2020 at 9:40

2

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I have my own helm chart and I'm trying to perform split without using the _helpers.tpl in one line my values.yaml file content: deployment: domain: my.domain I need to split domain name in my...
Multiplicity asked 5/12, 2018 at 14:31

4

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I would like to convert a part of the structure in values.yaml to properties file in a config map. Is it possible to convert a yaml structure like: field1: value1 field2: field21: value21 field...
Ers asked 12/2, 2020 at 8:40

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The below works {{- if hasKey (index $envAll.Values.policy) "type" }} {{- if has "two-wheeler" (index $envAll.Values.policy "type") }} <code goes here> {{- end }} {{- end }} while the bel...

3

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I'm trying to use a helm template helper to filter out values from a list in my values.yaml file, based on the value of one of the keys in each list member. My chart is currently comprised of thes...

1

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New to k8s & helm. Trying to declare a field in a deployment using the {{ .Release.Name }}, that must not contain characters other than letters (upper + lower), digits and _. Excluded charact...
Rivet asked 26/4, 2020 at 10:37

1

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Since Helm v3 built-in object .Release.Time is removed. What is the preferred way of injecting a release time into a template now?
Crook asked 10/4, 2020 at 12:52

1

Simple question is it possible to get size list with helm and sprig function ? My list : list: - a - b - c I tried like this : {{ .Values.list | len }} {{ .Values.list | size }} {{ .Values....
1

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