object-destructuring Questions

4

I get the following errors: type Union = { type: "1"; foo: string } | { type: "2"; bar: number }; function doSomething = (object: Union) => { const { foo } = object // ^ T...
Retrochoir asked 15/1, 2021 at 20:26

4

Solved

I am trying to extract variables using object destructuring but those variables already exist, something like this const x=1, y=2 // Those should be 1 and 2 const {x,y} = complexPoint const point ...

0

instead of this do this It could take only 2 lines not making my file longer than needed.

4

Object destructuring throws error in case of null object is passed function test ({name= 'empty'}={}) { console.log(name) } test(null); Uncaught TypeError: Cannot destructure pro...
Venitavenite asked 18/2, 2019 at 10:18

1

Solved

I saw this statement in Graphql directive definition: const { resolve = defaultFieldResolver } = field; I know the part const { resolve } = field; means getting resolve property of the field objec...
Weevily asked 4/6, 2021 at 23:20

8

Solved

Here is an example: const initObject = { a: 0, b: 0, c: 0 } const { a, ...rest } = initObject We're omitting property a from the object, but then const a is assigned a value, but never used ...
Bascio asked 15/5, 2019 at 14:23

3

Solved

I have been reading about Destructuring assignment introduced in ES6. What is the purpose of this syntax, why was it introduced, and what are some examples of how it might be used in practice?

3

Solved

I'm trying to spread an Error so that I can alter the error without affecting the original error. const error = new Error('Error test'); const freeError = {...error}; console.log(err...
Aristophanes asked 23/1, 2020 at 8:22

2

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This seems like a stupid question. Say I have a function which accepts an object. How can I cast that object as props, but also destructure props.id to id (in the parameter declaration)? funct...

1

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In Chrome version ^72 if I run the following JavaScript there are no errors. { prop: p } = { prop: 'prop' } >> { prop: 'prop' } So the line of code is interpreted as an expression statemen...
Maritamaritain asked 10/12, 2018 at 19:25

2

Solved

With ES6 you can destructure objects in function arguments: ({name, value}) => { console.log(name, value) } The equivalent ES5 would be: function(params) { console.log(params.name, pa...
Wingfooted asked 2/3, 2018 at 18:15

1

When destructuring objects in ES6 JS, you can use the { a, b } syntax in order to create new variables, called a and b respectively, from that object. However, as far as I can tell, there is ...
Kali asked 21/1, 2018 at 16:12

1

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Assume we have a function that use some keys in the inner object of argument: const api = ({ data: { name } = {} }) => `My name is ${name}.`; If we pass {}, { data: '' }, { data: 0 }, { ...
Fundus asked 23/5, 2017 at 15:14

1

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I'm looking at an ES6 class definition and don't understand the arguments to the constructor. Here's the class: export class Modal { constructor($modal, {size = null,} = {}) { // stuff } } I'...
Novikoff asked 5/5, 2016 at 18:54
1

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