implicit-constructor Questions

1

Assume we have procedure void f(X2);. Further assume we have types X1 and X2 that do not share an inheritance hierarchy. We want to call it like this: f(X1{}) and have X1 implicitly convert into X2...

1

Solved

Given the following code #include <iostream> using namespace std; template <typename Type> struct Something { Something() { cout << "Something()" << endl; } template...
Brittney asked 9/4, 2017 at 14:17
1

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