rspec yield block, but call original

Question

So I have the following:

foo.each do |f|
  f.begin
    do_stuff
    do_more_stuff
  end
end

And I mock the f object with an and_yield() call. I want to be able to test the begin method by passing it the original block { do_stuff do_more_stuff }, not a mock implementation.... I cant just let the begin method be called on the mock without at least stubbing it, so what do I do?

Soldierly

Answer 1

Again, an undocumented feature that i found:

allow(thing).to receive(:foo) do |_, &block|
  block.call
end

le sigh....

Soldierly

Not undocumented: relishapp.com/rspec/rspec-mocks/v/3-1/docs/… – Uncritical

Awesomesauce! I guess I am just blind – Soldierly

With RSpec 3.10.x, I had luck with and_wrap_original. rspec.info/documentation/3.3/rspec-mocks/RSpec/Mocks/… – Flatiron

Answer 2

The following worked for me:

original = thing.method(:foo)
expect(thing).to receive(:foo) do |_params|
  # check params
  expect(params).to include(something)

  # then
  original.call(params)
end

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