How to get streaming url from online streaming radio station

Question

I've been asked to make unofficial online streaming android application for a certain radio station.
I've experience with streaming in android for certain mp3 or whatever stream.
But I don't know the stream url to provide in mediaPlayer.setDataSource(url).

Is there any way to get the stream url from the ofiicial streaming page for ex. this radio stream?

Unprecedented

I don't ask here unless I can't find it on internet, I've googled and searched stakoverflow – Tush

Answer 1

not that hard,

if you take a look at the page source, you'll see that it uses to stream the audio via shoutcast.

this is the stream url

"StreamUrl": "http://stream.radiotime.com/listen.stream?streamIds=3244651&rti=c051HQVbfRc4FEMbKg5RRVMzRU9KUBw%2fVBZHS0dPF1VIExNzJz0CGQtRcX8OS0o0CUkYRFJDDW8LEVRxGAEOEAcQXko%2bGgwSBBZrV1pQZgQZZxkWCA4L%7e%7e%7e",

which returns a JSON like that:

{
    "Streams": [
        {
            "StreamId": 3244651,
            "Reliability": 92,
            "Bandwidth": 64,
            "HasPlaylist": false,
            "MediaType": "MP3",
            "Url": "http://mp3hdfm32.hala.jo:8132",
            "Type": "Live"
        }
    ]
}

i believe that's the url you need: http://mp3hdfm32.hala.jo:8132

this is the station WebSite

Brainard

That's it! before posting I tried inspect element and find something like that but I couldn't, thank you – Tush

I'm currently having the same problem I need to play audio at this website help me out – Cuttler

This can hardly qualify as an answer. It applies only to the station of the example given in the description! It doesn't apply to the question "How to get streaming url from online streaming radio station", which is for any radio station!! – Attorney

Answer 2

Edited ZygD's answer for python 3.x.:

import re
import urllib.request
import string
url1 = input("Please enter a URL from Tunein Radio: ");
request = urllib.request.Request(url1);
response = urllib.request.urlopen(request);
raw_file = response.read().decode('utf-8');
API_key = re.findall(r"StreamUrl\":\"(.*?),\"",raw_file);
#print API_key;
#print "The API key is: " + API_key[0];
request2 = urllib.request.Request(str(API_key[0]));
response2 = urllib.request.urlopen(request2);
key_content = response2.read().decode('utf-8');
raw_stream_url = re.findall(r"Url\": \"(.*?)\"",key_content);
bandwidth = re.findall(r"Bandwidth\":(.*?),", key_content);
reliability = re.findall(r"lity\":(.*?),", key_content);
isPlaylist = re.findall(r"HasPlaylist\":(.*?),",key_content);
codec = re.findall(r"MediaType\": \"(.*?)\",", key_content);
tipe = re.findall(r"Type\": \"(.*?)\"", key_content);
total = 0
for element in raw_stream_url:
    total = total + 1
i = 0
print ("I found " + str(total) + " streams.");
for element in raw_stream_url:
    print ("Stream #" + str(i + 1));
    print ("Stream stats:");
    print ("Bandwidth: " + str(bandwidth[i]) + " kilobytes per second.");
    print ("Reliability: " + str(reliability[i]) + "%");
    print ("HasPlaylist: " + str(isPlaylist[i]));
    print ("Stream codec: " + str(codec[i]));
    print ("This audio stream is " + tipe[i].lower());
    print ("Pure streaming URL: " + str(raw_stream_url[i]));
i = i + 1
input("Press enter to close")

Contingent

I had to append http: to the API Key: request2 = urllib.request.Request("http:%s" % API_key[0]); – Jurassic

Answer 3

The provided answers didn't work for me. I'm adding another answer because this is where I ended up when searching for radio stream urls.

Radio Browser is a searchable site with streaming urls for radio stations around the world:

http://www.radio-browser.info/

Search for a station like FIP, Pinguin Radio or Radio Paradise, then click the save button, which downloads a PLS file that you can open in your radioplayer (Rhythmbox), or you open the file in a text editor and copy the URL to add in Goodvibes.

Lamere

Answer 4

Shahar's answer was really helpful, but I found it quite tedious to do this all myself, so I made a nifty little Python program:

import re
import urllib2
import string
url1 = raw_input("Please enter a URL from Tunein Radio: ");
open_file = urllib2.urlopen(url1);
raw_file = open_file.read();
API_key = re.findall(r"StreamUrl\":\"(.*?),",raw_file);
#print API_key;
#print "The API key is: " + API_key[0];
use_key = urllib2.urlopen(str(API_key[0]));
key_content = use_key.read();
raw_stream_url = re.findall(r"Url\": \"(.*?)\"",key_content);
bandwidth = re.findall(r"Bandwidth\":(.*?),", key_content);
reliability = re.findall(r"lity\":(.*?),", key_content);
isPlaylist = re.findall(r"HasPlaylist\":(.*?),",key_content);
codec = re.findall(r"MediaType\": \"(.*?)\",", key_content);
tipe = re.findall(r"Type\": \"(.*?)\"", key_content);
total = 0
for element in raw_stream_url:
    total = total + 1
i = 0
print "I found " + str(total) + " streams.";
for element in raw_stream_url:
    print "Stream #" + str(i + 1);
    print "Stream stats:";
    print "Bandwidth: " + str(bandwidth[i]) + " kilobytes per second."
    print "Reliability: " + str(reliability[i]) + "%"
    print "HasPlaylist: " + str(isPlaylist[i]) + "."
    print "Stream codec: " + str(codec[i]) + "."
    print "This audio stream is " + tipe[i].lower() + "."
    print "Pure streaming URL: " + str(raw_stream_url[i]) + ".";
    i = i + 1
raw_input("Press enter to close TMUS.")

It's basically Shahar's solution automated.

Ferro

To get the whole list replace with this API_key = re.findall(r"StreamUrl\":\"(.*?),\"",raw_file) I just added \" on the regex – Pemberton

Answer 5

When you go to a stream url, you get offered a file. feed this file to a parser to extract the contents out of it. the file is (usually) plain text and contains the url to play.

Nutrient