data passing app in falcon python

Before asking the question i want to mention that i am aware of the fact that i can use django instead to make the app, but i need to use falcon and nothing else.

i am just looking for an approach

lets take a very simple scenario so that i can understand how data flows between various parts of the app.

i have a simple login page using html:

<!DOCTYPE html>
<html>
<body>

<form action="***what-do-i-put-here***">
  <fieldset>
    <legend>Personal information:</legend>
    First name:<br>
    <input type="text" name="firstname" value="Mickey">
    <br>
    Last name:<br>
    <input type="text" name="lastname" value="Mouse">
    <br><br>
    <input type="submit" value="Submit">
  </fieldset>
</form>

</body>
</html>

i run it using simpleHTTpServer present by default in python.

now i create a very basic falcon app with just one responder "on_post()" which just replies back with the data that it recieved from the form,

i am using uWsgi on localserver to host my falcon app. how do i the make these two different pieces of code to interact with each other i mean in the html form ,what we do in case of Php is we define the name of php file under "actions" tag .how do we do this in falcon.

a very simple and small working example is highly appreciated

<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Title</title> </head> <body> <form action="http://127.0.0.1:8000" method="post"> <input type="text" name="name"> <button type="submit" name="btn">Submit</button> </form> </body> </html>

import falcon from wsgiref import simple_server class Resource(object): def on_post(self, req, resp): resp.status = falcon.HTTP_200 resp.body = req.params['name'] app = api = falcon.API() app.req_options.auto_parse_form_urlencoded = True api.add_route('/', Resource()) if __name__ == '__main__': http = simple_server.make_server('127.0.0.1', 8000, app) http.serve_forever()

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