Using the following sequence of methods I was able to get a rough approximation. It is a very simple solution and might not work for all cases.
1. Morphological operations
To merge neighboring lines perform morphological (dilation) operations on the binary image.
img = cv2.imread('image_path', 0) # grayscale image
img1 = cv2.imread('image_path', 1) # color image
th = cv2.threshold(img, 150, 255, cv2.THRESH_BINARY)[1]
kernel = cv2.getStructuringElement(cv2.MORPH_ELLIPSE, (19, 19))
morph = cv2.morphologyEx(th, cv2.MORPH_DILATE, kernel)
2. Finding contours and extreme points
- My idea now is to find contours.
- Then find the extreme points of each contour.
- Finally find the closest distance among these extreme points between neighboring contours. And draw a line between them.
cnts1 = cv2.findContours(morph, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)`
cnts = cnts1[0] # storing contours in a variable
Lets take a quick detour to visualize where these extreme points are present:
# visualize extreme points for each contour
for c in cnts:
left = tuple(c[c[:, :, 0].argmin()][0])
right = tuple(c[c[:, :, 0].argmax()][0])
top = tuple(c[c[:, :, 1].argmin()][0])
bottom = tuple(c[c[:, :, 1].argmax()][0])
# Draw dots onto image
cv2.circle(img1, left, 8, (0, 50, 255), -1)
cv2.circle(img1, right, 8, (0, 255, 255), -1)
cv2.circle(img1, top, 8, (255, 50, 0), -1)
cv2.circle(img1, bottom, 8, (255, 255, 0), -1)
(Note: The extreme points points are based of contours from morphological operations, but drawn on the original image)
3. Finding closest distances between neighboring contours
Sorry for the many loops.
- First, iterate through every contour (split line) in the image.
- Find the extreme points for them. Extreme points mean top-most, bottom-most, right-most and left-most points based on its respective bounding box.
- Compare the distance between every extreme point of a contour with those of every other contour. And draw a line between points with the least distance.
for i in range(len(cnts)):
min_dist = max(img.shape[0], img.shape[1])
cl = []
ci = cnts[i]
ci_left = tuple(ci[ci[:, :, 0].argmin()][0])
ci_right = tuple(ci[ci[:, :, 0].argmax()][0])
ci_top = tuple(ci[ci[:, :, 1].argmin()][0])
ci_bottom = tuple(ci[ci[:, :, 1].argmax()][0])
ci_list = [ci_bottom, ci_left, ci_right, ci_top]
for j in range(i + 1, len(cnts)):
cj = cnts[j]
cj_left = tuple(cj[cj[:, :, 0].argmin()][0])
cj_right = tuple(cj[cj[:, :, 0].argmax()][0])
cj_top = tuple(cj[cj[:, :, 1].argmin()][0])
cj_bottom = tuple(cj[cj[:, :, 1].argmax()][0])
cj_list = [cj_bottom, cj_left, cj_right, cj_top]
for pt1 in ci_list:
for pt2 in cj_list:
dist = int(np.linalg.norm(np.array(pt1) - np.array(pt2))) #dist = sqrt( (x2 - x1)**2 + (y2 - y1)**2 )
if dist < min_dist:
min_dist = dist
cl = []
cl.append([pt1, pt2, min_dist])
if len(cl) > 0:
cv2.line(img1, cl[0][0], cl[0][1], (255, 255, 255), thickness = 5)
4. Post-processing
Since the final output is not perfect, you can perform additional morphology operations and then skeletonize it.