I am trying to get the IP address of an device i.e using WIFI or 3G connection. I am getting the ip address in IPV6 format which is not understandable. I want in IPV4 format IP address.I have done google but dint found any proper solutions.
here is code which I am using to get IP address of an device
public String getLocalIpAddress() {
try {
try {
for (Enumeration<NetworkInterface> en = NetworkInterface
.getNetworkInterfaces(); en.hasMoreElements();) {
NetworkInterface intf = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();)
{
InetAddress inetAddress = enumIpAddr.nextElement();
System.out.println("ip1--:" + inetAddress);
System.out.println("ip2--:" + inetAddress.getHostAddress());
if (!inetAddress.isLoopbackAddress()) {
String ip = inetAddress.getHostAddress().toString();
System.out.println("ip---::" + ip);
EditText tv = (EditText) findViewById(R.id.ipadd);
tv.setText(ip);
return inetAddress.getHostAddress().toString();
}
}
}
} catch (Exception ex) {
Log.e("IP Address", ex.toString());
}
return null;
}
I am getting this ouput :
ip1--:/fe80::5054:ff:fe12:3456%eth0%2
ip2--:fe80::5054:ff:fe12:3456%eth0
It should be displayed like this :
192.168.1.1
please help me out..