I need a calculate below expression using sympy in python?
exp = '(a+b)*40-(c-a)/0.5'
In a=6
, b=5
, c=2
this case how to calculate expression using sympy in python? Please help me.
I need a calculate below expression using sympy in python?
exp = '(a+b)*40-(c-a)/0.5'
In a=6
, b=5
, c=2
this case how to calculate expression using sympy in python? Please help me.
The documentation is here: http://docs.sympy.org/. You should really read it!
To "calculate" your expression, write something like this:
from sympy import Symbol
a = Symbol("a")
b = Symbol("b")
c = Symbol("c")
exp = (a+b)*40-(c-a)/0.5
And that's it. If you meant something else by "calculate", you could also solve exp = 0:
sympy.solve(exp)
> {a: [0.0476190476190476*c - 0.952380952380952*b],
> b: [0.05*c - 1.05*a],
> c: [20.0*b + 21.0*a]}
For everything else, you should really read the docs. Maybe start here: http://docs.sympy.org/0.7.1/tutorial.html#tutorial
UPDATE: since you added the values for a, b, c to the question, you can add this to the solution:
exp.evalf(subs={a:6, b:5, c:2})
You can convert your string into a sympy expression using the parse_expr()
function in the module sympy.parsing.sympy_parser
.
>>> from sympy.abc import a, b, c
>>> from sympy.parsing.sympy_parser import parse_expr
>>> sympy_exp = parse_expr('(a+b)*40-(c-a)/0.5')
>>> sympy_exp.evalf(subs={a:6, b:5, c:2})
448.000000000000
I realise this was already answered above, but in the case of getting a string expression with unknown symbols and needing access to those symbols, here is the code I used
# sympy.S is a shortcut to sympify
from sympy import S, Symbol
# load the string as an expression
expression = S('avar**2 + 3 * (anothervar / athirdvar)')
# get the symbols from the expression and convert to a list
# all_symbols = ['avar', 'anothervar', 'athirdvar']
all_symbols = [str(x) for x in expression.atoms(Symbol)]
# do something with the symbols to get them into a dictionary of values
# then we can find the result. e.g.
# symbol_vals = {'avar': 1, 'anothervar': 2, 'athirdvar': 99}
result = expression.subs(symbols_vals)
Well, I know that eval
is evil, but if you have a,b and c defined in your program, and you can make sure that it's safe to do the eval, you don't need sympy.
>>> a=5
>>> b=5
>>> c=2
>>> exp = '(a+b)*40-(c-a)/0.5'
>>> eval(exp)
406.0
>>> a, b, c = sympy.symbols('a b c')
>>> exp = (a + b) * 40 - (c - a) / 0.5
>>> exp.evalf(6, subs={a:6, b:5, c:2})
448.000
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