Ideally, Access SQL would have a PRODUCT
aggregate function available, but it doesn't. We can however simulate it by remembering what we learned about logarithms at school (or not...), and remembering that the anti-log of the sum of logs is equal to the product:
SELECT field2, EXP(Sum(LOG(Field3))) AS ProductOfField3
FROM t
GROUP BY Field2
Note that whereas a true PRODUCT
function would simply return 0
for a group if there are any zero values, this solution will fail if there are any zero values, so watch out for that. Also, this approach won't work if there are any negative values.
To deal with zeroes we could do this:
SELECT
field2,
EXP(Sum(LOG(IIf(Field3 = 0, 1, Field3)))) AS ProductOfField3,
MIN(ABS(Field3)) AS MinOfAbsField3
FROM t
GROUP BY Field2
and then disregard the ProductOfField3
value for any row where MinOfAbsField3
is zero (as this indicates a group containing a zero, thus the 'true' product should be 0
)
To deal with negative values we could further do this:
SELECT
field2,
EXP(Sum(LOG(IIf(Field3 = 0, 1, ABS(Field3))))) AS ProductOfField3,
MIN(ABS(Field3)) AS MinOfAbsField3,
SUM(IIf(Field3 < 0, 1, 0)) AS SumOfNegativeIndicator
FROM t
GROUP BY Field2
and interpret the results with these rules:
- If
MinOfAbsField3
is zero, disregard ProductOfField3
for that row - the product is zero
- Otherwise, the required answer for a given row is
ProductOfField3
, negated if SumOfNegativeIndicator
is odd in that row