According to the MSDN documentation for the WindowStartupLocation Property:
Setting CenterScreen causes a window to be positioned in the center of the screen that contains the mouse cursor.
Although the MSDN doc for the CenterScreen Field itself defines it somewhat less clearly as:
The startup location of a window is the center of the screen on which it is opened.
A simple test shows this working as it should:
MainWindow.xaml
<Window x:Class="CenterScreenTest.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
<Button Click="button_Click">Open Window</Button>
</Window>
MainWindow.xaml.cs
using System.Windows;
namespace CenterScreenTest
{
public partial class MainWindow
{
public MainWindow()
{
InitializeComponent();
}
void button_Click(object sender, RoutedEventArgs e)
{
Window window = new Window();
window.WindowStartupLocation = WindowStartupLocation.CenterScreen;
window.Show();
}
}
}
If you test this out on a dual monitor system, you can see that the new window will be centered on the screen where the mouse cursor is when you click the button. That's exactly how it should work.
However, if you try to set the window to maximize before you show it, the new window will only maximize on the display from which you launched the application. Change the button_Click event handler to the following to see what I mean:
void button_Click(object sender, RoutedEventArgs e)
{
Window window = new Window();
window.WindowStartupLocation = WindowStartupLocation.CenterScreen;
window.WindowState = WindowState.Maximized;
window.Show();
}
Now the window will only maximize on the screen from which the application is launched, no matter where the mouse cursor is when you click the button. If you set the window state to maximized after you show it, CenterScreen works properly. This is equivalent to the user maximizing the window. For instance:
void button_Click(object sender, RoutedEventArgs e)
{
Window window = new Window();
window.WindowStartupLocation = WindowStartupLocation.CenterScreen;
window.Show();
window.WindowState = WindowState.Maximized;
}
The problem here, of course, is that maximizing the window after showing it takes much longer and in an app such as mine, the window needs to pop into place immediately.
Anyone know of a solution?
WindowStartupLocation
toCenterScreen
to open it on the screen with the mouse cursor; then in theLoaded
event addthis.WindowState = WindowState.Maximized;
. (On Windows 10, it just opens maximized if you do this, and on the screen with the mouse cursor; since loaded fires before the window is first displayed.) – Coper