What does /i at the end of a regex mean?

Question

What is the meaning of /i at the tail of this regex?

var time = /^([1-9]|1[0-9]):([0-5][0-9])(\s[a|p]m)$/i;

Tonguing

Note that [a|p] matches a, | or p (yes, the | as well!). Inside a character set, the pipe has no special meaning. So you'll probably want to do: [ap]m which matches am or pm. – Hypnos

Also, you first part ([1-9]|1[0-9]) will only match '1', '2', '3', ... , '19'. Is that correct? – Hypnos

@Bart: Thanks. Now if I want digits-digits i.e xxxx-xx i.e n digits n then - and then one or two digits, my regex will look like this? /^\d+-\d{1,2}$/ or something else? – Tonguing

@Bart: I need your input here (#4967020) – Tonguing

Answer 1

/i stands for ignore case in the given string. Usually referred to as case-insensitive as pointed out in the comment.

Geniegenii

usually referred to as case-insensitive – Retroflex

@oneofthelions: Full syntax is readily available in the spec: ecma-international.org/publications/standards/Ecma-262.htm And there might be the odd website or two providing JavaScript regular expressions info in more accessible language. – Estragon

@Piskvor - yes, thanks. I totally forgot that word and had type incase-sensitive..:) Have edited my answer for this. – Geniegenii

Answer 2

It's, like Sachin Shanbhag already answered the 'ignore case' modifier. So /[a-z]/i is equal to /[a-zA-Z]/. Check this link for other modifiers.

Albina