You have to use the FormulaEvaluator, as shown here. This will return a value that is either the value present in the cell or the result of the formula if the cell contains such a formula :
FileInputStream fis = new FileInputStream("/somepath/test.xls");
Workbook wb = new HSSFWorkbook(fis); //or new XSSFWorkbook("/somepath/test.xls")
Sheet sheet = wb.getSheetAt(0);
FormulaEvaluator evaluator = wb.getCreationHelper().createFormulaEvaluator();
// suppose your formula is in B3
CellReference cellReference = new CellReference("B3");
Row row = sheet.getRow(cellReference.getRow());
Cell cell = row.getCell(cellReference.getCol());
if (cell!=null) {
switch (evaluator.evaluateFormulaCell(cell)) {
case Cell.CELL_TYPE_BOOLEAN:
System.out.println(cell.getBooleanCellValue());
break;
case Cell.CELL_TYPE_NUMERIC:
System.out.println(cell.getNumericCellValue());
break;
case Cell.CELL_TYPE_STRING:
System.out.println(cell.getStringCellValue());
break;
case Cell.CELL_TYPE_BLANK:
break;
case Cell.CELL_TYPE_ERROR:
System.out.println(cell.getErrorCellValue());
break;
// CELL_TYPE_FORMULA will never occur
case Cell.CELL_TYPE_FORMULA:
break;
}
}
if you need the exact contant (ie the formla if the cell contains a formula), then this is shown here.
Edit :
Added a few example to help you.
first you get the cell (just an example)
Row row = sheet.getRow(rowIndex+2);
Cell cell = row.getCell(1);
If you just want to set the value into the cell using the formula (without knowing the result) :
String formula ="ABS((1-E"+(rowIndex + 2)+"/D"+(rowIndex + 2)+")*100)";
cell.setCellFormula(formula);
cell.setCellStyle(this.valueRightAlignStyleLightBlueBackground);
if you want to change the message if there is an error in the cell, you have to change the formula to do so, something like
IF(ISERR(ABS((1-E3/D3)*100));"N/A"; ABS((1-E3/D3)*100))
(this formula check if the evaluation return an error and then display the string "N/A", or the evaluation if this is not an error).
if you want to get the value corresponding to the formula, then you have to use the evaluator.
Hope this help,
Guillaume
cell.getStringCellValue();
orcell.getNumericCellValue();
. Your answer applies to situations where the cell contains a formula, there is no indication that's the case for the OP – Annals