I want to return status code different from 100 <= self.status_code <= 599
, as written in Django's HttpResponseBase class. Is there are any easy way to bypass this restriction?
How do I return custom response/status code in Django?
Asked Answered
The HTTP codes have ranges, for example 100-199 is information, 200-299 is success, 300-399 redirection, etc. So it does not make much sense to return a status code outside this range. Especially since a browser will typically for example redirect in case of a 301/302. –
Fraser
You can, if you really want, patch the .status_code
attribute. For example with:
from django.http import HttpResponse
def some_view(request):
response = HttpResponse('some data')
response.status_code = 754 # sample status code
return response
But it does not make much sense to specify a HTTP status code [wiki] outside the 100-599 range, since these are subdivided into subranges that specify in what case to return what status code.
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