I am surprised that networkx does not seem to have a built in function to do this, but maybe I am missing some clever way to do this using the built-in algorithms?
When using the find_cliques function you need to be carfull when you are going through all the possibilities (itertools.combinations) - in some cases you will count the same clique more than once. For example, if you have a graph of six nodes (let's name them A-G). Four of them are fully connected (A-D) and E is connected to A-D, and G is also connected to A-D (but E is not connected to G). In this situation you have two 5-cliques that share 4 nodes (A,B,C,D,E and A,B,C,D,G). Now let's say that you are looking for 4-cliques in this suggested garph, by using find_cliques you will go over the two 5-cliques, and in each one of them you will count every 4-clique, which includes the 4-clique A,B,C,D, so it will be counted twice (!).
here is a version of the suggested function that fix this problem by using set so you will count each clique only once:
def find_cliques_size_k(G, k):
all_cliques = set()
for clique in nx.find_cliques(G):
if len(clique) == k:
all_cliques.add(tuple(sorted(clique)))
elif len(clique) > k:
for mini_clique in itertools.combinations(clique, k):
all_cliques.add(tuple(sorted(mini_clique)))
return len(all_cliques)
(If you want the cliques themselves you can return the 'all_cliques' itself)
You can use one of these built in functions: enumerate_all_cliques or find_cliques in order to get all k-clique in an un-directed graph.
The difference between these functions is that enumerate_all_cliques
goes over all possible cliques and find_cliques
goes over only the maximal cliques. We will see in the end it affects the run time.
Option 1 using enumerate_all_cliques
:
import networkx as nx
def enumerate_all_cliques_size_k(G, k):
i = 0
for clique in nx.enumerate_all_cliques(G):
if len(clique) == k:
i += 1
elif len(clique) > k:
return i
return i
Option 2 using find_cliques
:
import networkx as nx
import itertools
def find_cliques_size_k(G, k):
i = 0
for clique in nx.find_cliques(G):
if len(clique) == k:
i += 1
elif len(clique) > k:
i += len(list(itertools.combinations(clique, k)))
return i
The first option is more straight forward but it's run time is problematic since we go over all possible sub-sets of the maximal cliques, even if the maximal clique size is less than k.
We can see enumerate_all_cliques_size_k
takes 10 times longer to run on a complete graph of size 20:
G = nx.complete_graph(20)
@timing
def test_enumerate_all_cliques_size_k(G,k):
print(enumerate_all_cliques_size_k(G, k))
@timing
def test_find_cliques_size_k(G, k):
print(find_cliques_size_k(G, k))
test_enumerate_all_cliques_size_k(G,5)
test_find_cliques_size_k(G,5)
# --------------------Result-----------------------
15504
test_enumerate_all_cliques_size_k function took 616.645 ms
15504
test_find_cliques_size_k function took 56.967 ms
len(itertools.combinations(clique, k))
is easy to compute. –
Cooker len
won't work on an iterator but it is possible to use cardinality.count or to implement n choose k function –
Bartels When using the find_cliques function you need to be carfull when you are going through all the possibilities (itertools.combinations) - in some cases you will count the same clique more than once. For example, if you have a graph of six nodes (let's name them A-G). Four of them are fully connected (A-D) and E is connected to A-D, and G is also connected to A-D (but E is not connected to G). In this situation you have two 5-cliques that share 4 nodes (A,B,C,D,E and A,B,C,D,G). Now let's say that you are looking for 4-cliques in this suggested garph, by using find_cliques you will go over the two 5-cliques, and in each one of them you will count every 4-clique, which includes the 4-clique A,B,C,D, so it will be counted twice (!).
here is a version of the suggested function that fix this problem by using set so you will count each clique only once:
def find_cliques_size_k(G, k):
all_cliques = set()
for clique in nx.find_cliques(G):
if len(clique) == k:
all_cliques.add(tuple(sorted(clique)))
elif len(clique) > k:
for mini_clique in itertools.combinations(clique, k):
all_cliques.add(tuple(sorted(mini_clique)))
return len(all_cliques)
(If you want the cliques themselves you can return the 'all_cliques' itself)
Welcome to SO.
Based on this reference, I think currently there is no existing function to do this. If you want to use nx
functions you can do something like this:
def count_k_cliques(G, k):
k_cliques_count = 0
for clique in nx.enumerate_all_cliques(G):
if len(clique) > k:
break
elif len(clique) == k:
k_cliques_count += 1
return k_cliques_count
Edit: I recommend considering option 2 in Michal's answer
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