Why is the C++20 concept not compatible with "const auto&"?
Asked Answered
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template<typename T>
concept Octet = 1 == sizeof(T);

// ok
Octet decltype(auto) c = 'a';

// ok
void f1(const auto&) {}

// ok
void f2(Octet auto) {}

// ok
void f3(Octet auto&&) {}

// error: expected ‘auto’ or ‘decltype(auto)’ after ‘Octet’
void f4(Octet const auto&) {}

// error: cannot declare a parameter with ‘decltype(auto)’
void f5(Octet decltype(auto)) {}

Compiled with gcc-11 -std=c++20. See: https://godbolt.org/z/xK769Pfjn

Why do f4 and f5 not work?

Nitpicking answered 7/5, 2021 at 18:14 Comment(6)
Hmmm is the language finally enforcing right const? 🤔Kussell
Octet auto represents the type. You can have right const or left const, but not "middle-const".Euxenite
Why does f5 not work? @DrewDormannNitpicking
please add the complete compiler error message. I suppose this is gcc, because clangs error is different (although not much more helping)Hulking
All necessary messages are included. @largest_prime_is_463035818Nitpicking
@Nitpicking f5 is not valid C++ syntax. It has no meaning. You could perhaps look at this question to see the contexts where decltype(auto) has meaning in C++. Or perhaps you could edit the question to describe what you think that parameter would mean.Euxenite
Y
5

As seen in [dcl.spec.auto], when you use a placeholder here, the constraint needs to immediately precede the auto:

placeholder-type-specifier:
type-constraint_opt auto
type-constraint_opt decltype ( auto )

This is simply a matter of syntax. The constraint isn't a general specifier like const is; it doesn't have a flexible position. Conceptually, you can think of Octet auto as one "word" representing the constrained type.

As for f5, this is not allowed as a parameter per p2:

A placeholder-type-specifier of the form "type-constraint_opt auto" can be used as a decl-specifier of the decl-specifier-seq of a parameter-declaration of a function declaration...

No such text exists for decltype(auto). In addition, per p6:

A program that uses a placeholder type in a context not explicitly allowed in this subclause is ill-formed.

Logically, I'm not sure how I'd specify decltype(auto) to work in this context. Sure, it could be specified, but I don't think there's precedent in the language for it, so it would need to be motivated over an alternative that already has the desired effect.

Youngman answered 7/5, 2021 at 18:32 Comment(0)

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