I've found two related questions:
But I want to be specific. How to?
while not done:
for e in event.get():
if e.type == KEYDOWN:
keys = key.get_pressed()
if e.type == QUIT or keys[K_ESCAPE]:
done = True
if keys[K_DOWN]:
print "DOWN"
When I press the down arrow, it prints, but it prints just once. If I want to print it another time, I need to press it again.
If I use the while keyword instead,
while keys[K_DOWN]:
print "DOWN"
I get an infinite loop for some obscure reason.
This logical alternative is also useless:
if ((e.type == KEYDOWN) and keys[K_DOWN]):
print "DOWN"
And there is this other one that somehow cleans the events and you can use while:
while not done:
for e in event.get():
if e.type == KEYDOWN:
keys = key.get_pressed()
if e.type == QUIT or keys[K_ESCAPE]:
done = True
while keys[K_DOWN]:
print "DOWN"
event.get()
keys = key.get_pressed()
But you press the down key for less than one second and it prints thousands of times. (Moving a player would be impossible, and adjusting clock for this does not seem to be the right way to deal with it (And I've tried and I've failed miserably.)).
To press and execute the block thousands of times is useless. What I want, is to press the key and keep going with the action while I don't release it, within the defined game clock speed.
ve just added "print event.get()" and started to see and understand how it works, and you're right. If I loop through all the event list at each frame, it gets the pressed, and then returns it, and gets the released later on (It does not keep pressing while the key is down. The KEYDOWN is just an opposite for RELEASED, not "hold"). It's not possible to hold the key. The problem is that with the wait() function, the result is exactly the same. It waits for the keypressed, but I, with the button held, don
t get anymore keypresses until I RELEASE and then press it again. – Baccalaureate