Telegram channel- how to get access_hash?

Question

I try really hard to understand howto use Telegram api with telethon. I have some Channels in Telegram, where i want to delete older Messages. Using inputpeerchannel() i need channel_id (No Problem) and channel_hash. I cant findout howto get this channel_hash by channel_id. Thank you from germany

Contraceptive

have you found a solution? – Idellaidelle

Can anyone share an updated solution please? – Coracoid

Answer 1

In order to find channel access_hash, you should resolve channel username. Original MTProto method contacts.resolveUsername#f93ccba3 gets @username and returns channel info including access_hash.

In telethon you need to invoke ResolveUsernameRequest to call the above original MTProto method. You may use this code to resolve username to access_hash:

client = TelegramClient(session_file, api_id=00000, api_hash='XXXXX')
client.connect()
response = client.invoke(ResolveUsernameRequest("your_channel_id"))
print(response.chats[0].access_hash)
client.disconnect()

Sequent

"your_channel_id" is the username or the channel_id? it does not work for me with the channel_id, it works with the username but I only have the channel_id – Idellaidelle

"your_channel_id" is a string and it's the username. You can't access a channel only by channel_id. You need access_hash too. – Sequent

Do you know if the access_hash will be expired? – Buehrer

Answer 2

There are 4 ways to get access hash:

1. From a Group
2. From username
3. From contact list
4. From chats message

So, if you have id only, there is no way to get access hash

Changeful

but where is this user_hash? – Hudnut

You need to use the method provide by telegram, after that you get an object containing information about ID, Access_Hash, Name,... – Changeful

Could you clarify how exactly is possible to get access_hash from a group? – Nosewheel

Answer 3

Here is the updated code. replace appid, apphash and username

with TelegramClient('session.session', <app-id>,<app-hash>') as client:
result = client(functions.contacts.ResolveUsernameRequest(
    username=<username>
))
print(result.stringify())

Contretemps