Is there a simple way to switch between using and ignoring metacharacters in Python regular expressions?
Asked Answered
M

2

6

Is there a way of toggling the compilation or use of metacharacters when compiling regexes? The current code looks like this:


Current code:

import re

the_value  = '192.168.1.1'
the_regex  = re.compile(the_value)

my_collection = ['192a168b1c1', '192.168.1.1']

my_collection.find_matching(the_regex)

result = ['192a168b1c1', '192.168.1.1']


The ideal solution would look like:

import re

the_value  = '192.168.1.1'
the_regex  = re.compile(the_value, use_metacharacters=False)

my_collection = ['192a168b1c1', '192.168.1.1']

my_collection.find_matching(the_regex)

result = ['192.168.1.1']

The ideal solution would let the re library handle the disabling of metacharacters, to avoid having to get involved in the process as much as possible.

Millerite answered 22/11, 2013 at 2:35 Comment(1)
if you're looking for a static string, why do you want to use the re module? Why not just compare strings for equality, or search for a substring?Debus
E
7

Nope. However:

the_regex  = re.compile(re.escape(the_value))
Enunciation answered 22/11, 2013 at 2:37 Comment(0)
H
7

Use the re.escape() function for this.

Return string with all non-alphanumerics backslashed; this is useful if you want to match an arbitrary literal string that may have regular expression metacharacters in it.

>>> import re
>>> re.escape('192.168.1.1')
'192\\.168\\.1\\.1'
Habitancy answered 22/11, 2013 at 3:15 Comment(2)
Thanks! I'm accepting Ignacio's answer because it's technically the full solution. However, I appreciate your answer and your help :).Millerite
Whereas I think this is the better answer as it links to and quotes the documentation…Schistosomiasis

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