I have trouble understanding the sentence with respect to inline and customers binary compatibility. Can someone please explain?
C++ FAQ Cline, Lomow:
When the compiler synthesizes the copy constructor, it makes them inline. If your classes are exposed to your customers ( for example, if your customers #include your header files rather than merely using an executable, built from your classes ), your inline code is copied into your customers executables. If your customers want to maintain binary compatibilty between releases of your header files, you must not change an inline functions that are visible to the customers. Because of this, you will want an explicit, non inline version of the copy constructor, that will be used directly by the customer.