I know about int
and long
(32-bit and 64-bit numbers), but what are uint
and ulong
?
The primitive data types prefixed with "u" are unsigned versions with the same bit sizes. Effectively, this means they cannot store negative numbers, but on the other hand they can store positive numbers twice as large as their signed counterparts. The signed counterparts do not have "u" prefixed.
The limits for int (32 bit) are:
int: –2147483648 to 2147483647
uint: 0 to 4294967295
And for long (64 bit):
long: -9223372036854775808 to 9223372036854775807
ulong: 0 to 18446744073709551615
uint
and ulong
are the unsigned versions of int
and long
. That means they can't be negative. Instead they have a larger maximum value.
Type Min Max CLS-compliant int -2,147,483,648 2,147,483,647 Yes uint 0 4,294,967,295 No long –9,223,372,036,854,775,808 9,223,372,036,854,775,807 Yes ulong 0 18,446,744,073,709,551,615 No
To write a literal unsigned int in your source code you can use the suffix u
or U
for example 123U
.
You should not use uint and ulong in your public interface if you wish to be CLS-Compliant.
Read the documentation for more information:
By the way, there is also short and ushort and byte and sbyte.
u
means unsigned
, so ulong
is a large number without sign. You can store a bigger value in ulong
than long
, but no negative numbers allowed.
A long
value is stored in 64-bit,with its first digit to show if it's a positive/negative number. while ulong
is also 64-bit, with all 64 bit to store the number. so the maximum of ulong is 2(64)-1, while long is 2(63)-1.
The difference is that the uint
and ulong
are unsigned data types, meaning the range is different: They do not accept negative values:
int range: -2,147,483,648 to 2,147,483,647
uint range: 0 to 4,294,967,295
long range: –9,223,372,036,854,775,808 to 9,223,372,036,854,775,807
ulong range: 0 to 18,446,744,073,709,551,615
Based on the other answers here and a little review you can understand it this way: unsigned is in reference to the assignment of a negative or positive explicit assignment (think the "-" in -1) and the inability to have negative versions of said numbers.
And because of this capacity on the negative end being removed as an option they instead allocated that capacity to the positive end hence the doubling of the positive valuation's maximum value. So instead of the bit range being split along positive and negative valuations, they are instead for ushort, uint, along, etc allocated to the positive end of the valuation.
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