JSONArray response with Volley for Android
Asked Answered
C

2

9

I am posting some data into the database using Volley and I get the following jsonarray response.

[
  {
  "nickname":"panikos",
  "username":"[email protected]",
  "user_type":"LEADER",
  "latest_steps":"0"
  }
]

This is a sample of my code that unfortunately doesn't log out or debug the variable of "nickname" object:(.

final JsonArrayRequest jsonObjReq1 = new 
JsonArrayRequest(AppConfig.URL_GET_TEAM, jsonObject,
            new com.android.volley.Response.Listener<JSONArray>() {

                @Override
                public void onResponse(JSONArray response) {
                    Log.d("TAG", response.toString());

                    try {
                        JSONArray jsonArray = new JSONArray(response);

                        for(int i=0;i<jsonArray.length();i++){
                            JSONObject jresponse = 
                jsonArray.getJSONObject(i);
                String nickname =                                 
           jresponse.getString("nickname");
                            Log.d("nickname",nickname);
                        }
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                    //pDialog.dismiss();

                }
            }, new com.android.volley.Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            VolleyLog.d("TAG", "Error: " + error.getMessage());
            //pDialog.dismiss();

        }
    }) {

        @Override
        public String getBodyContentType() {
            return "application/json; charset=utf-8";
        }


    };

Any ideas? Am I missing something?

Thanks.

Cleotildeclepe answered 22/5, 2015 at 19:4 Comment(1)
the code seems okay. are you adding jsonObjReq1 to request queue ?Sonorous
S
8

I the problem might be - you are already getting response as a JSONArray.

So, you can Call

JSONObject jresponse = response.getJSONObject(0);

and if you have more than 1 object in response, then

for(int i = 0; i < response.length(); i++){
    JSONObject jresponse = response.getJSONObject(i);
    String nickname = jresponse.getString("nickname");
    Log.d("nickname", nickname);
}

Remove this :

               try {
                    JSONArray jsonArray = new JSONArray(response);

                    for(int i=0;i<jsonArray.length();i++){
                        JSONObject jresponse = 
            jsonArray.getJSONObject(i);
            String nickname =                                 
       jresponse.getString("nickname");
                        Log.d("nickname",nickname);
                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                }

and add :

try {
    JSONObject jresponse = response.getJSONObject(0);
    String nickname = jresponse.getString("nickname");
    Log.d("nickname",nickname);
}catch (JSONException e) {
    e.printStackTrace();
}

The Code looks good, however i think you might be missing a call to add jsonObjReq1 in the request queue. I would suggest to use Singleton Pattern.

Sonorous answered 22/5, 2015 at 19:17 Comment(8)
Thanks for the reply. Yes jsonObjReq1 is in the queue.Cleotildeclepe
AppController.getInstance().addToRequestQueue(jsonObjReq1, tag_json_obj);Cleotildeclepe
But I don't whats wrong and can't read the nickname object. It's so annoying!Cleotildeclepe
nope. I don't get any errors. I just put a breakpoint inside the onErrorResponse method and so nothing.Cleotildeclepe
The breakpoint in JSONArray jsonArray = new JSONArray(response); gives the JSON Array response. So it gets there. After that things are getting messy.Cleotildeclepe
I think if the app is not crashing, but must be leaving a volley log. can you show the logSonorous
org.json.JSONException: Not a primitive array: class org.json.JSONArrayCleotildeclepe
at app.victory.walking.thewalkingviktory.InvitationBoard$4.onResponse(InvitationBoard.java:189)Cleotildeclepe
C
1

Fixed!!!

                @Override
                public void onResponse(JSONArray response) {
                    Log.d("TAG", response.toString());

                    try {

                        Log.d("JsonArray",response.toString());
                        for(int i=0;i<response.length();i++){
                            JSONObject jresponse = response.getJSONObject(i);
                            String nickname = jresponse.getString("nickname");
                            Log.d("nickname",nickname);
                        }
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                    //pDialog.dismiss();

                }

There was no need to create a new JSONArray. It was created inside the onResponse() method. The next project I am assigned to do is going to have more complicate webservices.omg!!!

Cleotildeclepe answered 22/5, 2015 at 19:51 Comment(2)
You don't have to and your own question .. Please accept my and if it was helpfulSonorous
Hey, I am getting can not resolve getJSONObject(int). Any guesses?Pahlavi

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